CAPM - Predictive, Plan-Based Methodologies (17% of the exam) - Section 2.2

Develop a project schedule using activity sequencing, duration estimation, and the critical path method to identify total float and the longest path.

Sequence activities, estimate durations, and build a network diagram, then apply the critical path method to find the longest path through the project and the total float available on non-critical activities. Recognise that activities on the critical path have zero float and that schedule compression techniques - crashing and fast tracking - shorten the schedule at the cost of resources or added risk.

Critical path methodTotal floatSchedule baselineCrashingFast tracking

Practice question for this objective

Free samplePredictive, Plan-Based Methodologieshard

A scheduler has completed both the forward pass and the backward pass on a predictive project schedule and now wants to explain to the team what the critical path actually represents. Which statement correctly describes the critical path?

  • AIt is the sequence of activities with the greatest total float, which gives the schedule its maximum flexibility.
  • BIt is the longest path through the network, and its activities have zero total float. Correct
  • CIt is the path that contains the single longest-duration activity in the whole schedule.
  • DIt is the shortest path through the network, along which any delay is absorbed by available float.
Critical path activities lie on the longest network path and carry zero total float, so any delay to them delays the project. The forward and backward passes reveal that the longest path has identical early and late dates, producing zero total float. That absence of slack is what makes those activities critical and defines the project's shortest possible duration.

Why A is wrong: This inverts the concept. Activities with large total float can be delayed without affecting the finish date, so they are the least constraining, not the critical path. Critical activities have the least float, not the most.

Why B is correct: The critical path is the longest duration path from start to finish, so it drives the earliest completion date. Because there is no slack anywhere along it, each of its activities has zero total float, meaning any delay pushes the project end out.

Why C is wrong: A long individual activity may sit on a short path, while many shorter activities in sequence can form a longer path. Critical path length comes from the sum along a path, not from any one activity, so this is a common trap.

Why D is wrong: This reverses the definition. The shortest path has the most slack and delays there are indeed absorbed by float, which is exactly why it is not critical. The critical path is the longest path and has no float to absorb delay.

See more CAPM practice questions, answers explained.

Exam traps in Predictive, Plan-Based Methodologies

Answers that look right on this material and are not. Each one is a distractor from a different question in the CAPM bank for this domain.

  • A-B-D-F, 16 days

    Why it is wrong: A-B-D-F sums to 4+3+5+4=16 days; this is the near-critical path carrying one day of total float, so it is not the longest chain and does not drive the finish date.

  • B to D to E, with a total duration of 15 days

    Why it is wrong: B to D to E is the near-critical path at 15 days and carries only 1 day of total float. It is tempting because it starts with the longest single activity, B at 6 days, but a longer path exists, so it is not critical.

  • 0 days

    Why it is wrong: Zero float assumes C lies on the longest path, but A-B-D runs 15 days while A-C-E runs only 14 days, so C is not on the critical path and does carry float.

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